My inquiry is regarding how this process would function similarly when the script is executed within an AWS Lambda function.
11 answers
Thankyou it solved my issue.
To the best of my knowledge, the itemname referenced here pertains to the file that the function is retrieving and processing.
What is itemname here?
s3client.download_file(bucket_name, obj.key, '/tmp/'+filename) ... blank_file = open('/tmp/blank_file.txt', 'w')
The working directory for Lambda is located at /var/task, which is a read-only filesystem. Consequently, file creation within this directory is not permitted.
To know more about AWS lambda and its features in detail check this out! https://www.youtube.com/watch?v=XjPUyGKRjZs
You can download the file from AWS S3 bucket
import boto3
bucketname = 'my-bucket' # replace with your bucket name
filename = 'my_image_in_s3.jpg' # replace with your object key
s3 = boto3.resource('s3')
s3.Bucket(bucketname).download_file(filename, 'my_localimage.jpg')
Use this code to download the file from aws.
import boto3
s3 = boto3.resource("s3")
srcFileName="abc.txt"
destFileName="s3_abc.txt"
bucketName="mybucket001"
k = Key(bucket,srcFileName)
k.get_contents_to_filename(destFileName)
This is the code i found and can be used to read the file from S3 bucket using lambda function
def lambda_handler(event, context):
# TODO implement
import boto3
s3 = boto3.client('s3')
data = s3.get_object(Bucket='my_s3_bucket', Key='main.txt')
contents = data['Body'].read()
print(contents)
You can use this function to read the file
exports.handler =(event, context, callback) => {
var bucketName = process.env.bucketName;
var keyName = event.Records[0].s3.object.key;
readFile(bucketName, keyName, readFileContent, onError);
};
https://docs.aws.amazon.com/lambda/latest/dg/with-s3-example.html
This contains the code to do that with examples.
import boto3 client = boto3. client('s3') #low-level functional API resource = boto3.
import pandas as pd obj = client. get_object(Bucket='my-bucket', Key='path/to/my/table.csv') grid_sizes = pd.
from io import BytesIO obj = client.
my_bucket.
files = list(my-bucketTo establish and execute this example, you need to:
1. Set up your AWS credentials as detailed in the Quickstart guide.
2. Create an S3 bucket and upload a file to it.
3. Substitute the BUCKET_NAME and KEY placeholders in the code snippet with your bucket's name and the key corresponding to the uploaded file.
I executed this code, but it is displaying a task timeout error. Could someone please explain the possible reasons for this issue?